Area and Volume GCSE Foundation Formula Guide
Area and volume GCSE formulas explained for resit students, with clear worked examples on perimeter, circles, trapeziums, prisms and units.

A formula can feel perfectly familiar until an exam question wraps it inside a garden, a floor plan or a prism. Then the difficulty is not always the arithmetic. It is deciding what the question wants, choosing the right measurements and giving the answer in the correct units.
This area and volume GCSE guide covers the foundation formulas you need for rectangles, triangles, trapeziums, circles and prisms. It also shows each method through a worked example. For resit students, the aim is not to memorise a crowded page overnight. It is to build a short sequence you can trust: identify the shape, choose the formula, substitute carefully and check the units.
Your foundation formula checklist
| Shape or measurement | Formula |
|---|---|
| Rectangle perimeter | P=2l+2wP=2l+2wP=2l+2w |
| Rectangle area | A=lwA=lwA=lw |
| Triangle area | A=12bhA=\frac{1}{2}bhA=21bh |
| Trapezium area | A=12(a+b)hA=\frac{1}{2}(a+b)hA=21(a+b)h |
| Circle circumference | C=πdC=\pi dC=πd or C=2πrC=2\pi rC=2πr |
| Circle area | A=πr2A=\pi r^2A=πr2 |
| Prism volume | V=area of cross-section×lengthV=\text{area of cross-section}\times\text{length}V=area of cross-section×length |
Here, lll is length, www is width, bbb is base, hhh is perpendicular height, rrr is radius and ddd is diameter. In the trapezium formula, aaa and bbb are the parallel sides.
Formula sheets and question wording can vary, so make formula recall part of your preparation rather than assuming every expression will be provided. You can strengthen the basics with the Area and Perimeter GCSE revision lesson, then use the Area and Perimeter exam-style questions to practise recognising which formula is needed.
Perimeter GCSE questions measure the outside
Perimeter is the total distance around a flat shape. It uses ordinary length units such as mm\text{mm}mm, cm\text{cm}cm or m\text{m}m.
This distinction matters. Area measures the space inside a shape, while perimeter measures its boundary. If a question asks for fencing around a field, edging around a floor or the total length of a shape's sides, it is asking for perimeter.
Worked example: rectangle perimeter
A rectangular noticeboard is 1.8 m1.8\text{ m}1.8 m long and 0.9 m0.9\text{ m}0.9 m wide. Find its perimeter.
Use:
P=2l+2w P=2l+2w P=2l+2wSubstitute the dimensions:
P=2(1.8)+2(0.9) P=2(1.8)+2(0.9) P=2(1.8)+2(0.9) P=3.6+1.8 P=3.6+1.8 P=3.6+1.8 P=5.4 m P=5.4\text{ m} P=5.4 mThe answer is in metres, not square metres, because perimeter is a length.
For an irregular polygon, add every outside edge. If a length is missing, you may need to work it out from the other dimensions before finding the perimeter. Marking each side as you add it can prevent omissions.
Finding the area of a rectangle
The area of a rectangle is:
A=lw A=lw A=lwWorked example: rectangle area
A floor is 4.5 m4.5\text{ m}4.5 m long and 3.2 m3.2\text{ m}3.2 m wide. Find its area.
A=4.5×3.2 A=4.5\times3.2 A=4.5×3.2 A=14.4 m2 A=14.4\text{ m}^2 A=14.4 m2Area uses square units because the surface could be covered by unit squares. A common resit mistake is to calculate correctly and write 14.4 m14.4\text{ m}14.4 m. That describes a length, not an area.
Compound rectilinear shapes are often built from rectangles. Split the shape into non-overlapping rectangles, find each area and add the results. Alternatively, complete a larger rectangle and subtract the missing section. Both approaches are valid when they are shown clearly.
Finding the area of a triangle
A triangle's area is half the area of a rectangle with the same base and perpendicular height:
A=12bh A=\frac{1}{2}bh A=21bhThe height must be perpendicular to the base. A sloping side is not automatically the height. Look for a right-angle marker or a line that meets the base at 90∘90^\circ90∘.
Worked example: triangle area
A triangle has a base of 12 cm12\text{ cm}12 cm and a perpendicular height of 7 cm7\text{ cm}7 cm. Find its area.
A=12×12×7 A=\frac{1}{2}\times12\times7 A=21×12×7 A=6×7 A=6\times7 A=6×7 A=42 cm2 A=42\text{ cm}^2 A=42 cm2Writing the formula before substituting makes your reasoning visible. It also gives you a moment to notice the factor of 12\frac{1}{2}21, which is easy to miss under exam pressure.
Finding the area of a trapezium
A trapezium has one pair of parallel sides. Its area is:
A=12(a+b)h A=\frac{1}{2}(a+b)h A=21(a+b)hThe letters aaa and bbb represent the parallel sides. The value hhh is the perpendicular distance between them.
One way to remember the process is: add the parallel sides, multiply by the perpendicular height, then divide by 222.
Worked example: trapezium area
A trapezium has parallel sides of 9 cm9\text{ cm}9 cm and 15 cm15\text{ cm}15 cm. Its perpendicular height is 6 cm6\text{ cm}6 cm. Find its area.
A=12(9+15)×6 A=\frac{1}{2}(9+15)\times6 A=21(9+15)×6 A=12×24×6 A=\frac{1}{2}\times24\times6 A=21×24×6 A=72 cm2 A=72\text{ cm}^2 A=72 cm2Do not use the two sloping sides in place of aaa and bbb. A useful first step is to mark the matching parallel sides on the diagram.
Circle area GCSE formulas
Circle questions involve two different measurements. Circumference is the distance around the circle. Area is the space inside it.
The formulas are:
C=2πr C=2\pi r C=2πr C=πd C=\pi d C=πd A=πr2 A=\pi r^2 A=πr2The diameter passes all the way through the centre. The radius goes from the centre to the circumference, so:
d=2r d=2r d=2rWorked example: area of a circle
A circle has a diameter of 10 cm10\text{ cm}10 cm. Find its area, giving the answer to 111 decimal place.
The formula needs the radius, so halve the diameter:
r=10÷2=5 cm r=10\div2=5\text{ cm} r=10÷2=5 cmNow substitute:
A=πr2 A=\pi r^2 A=πr2 A=π×52 A=\pi\times5^2 A=π×52 A=25π A=25\pi A=25πUsing a calculator:
A=78.539… A=78.539\ldots A=78.539…To 111 decimal place:
A=78.5 cm2 A=78.5\text{ cm}^2 A=78.5 cm2Keep the full calculator value until the final step. Rounding π\piπ to 3.143.143.14 too early can make a final answer less accurate. If the question requests an exact answer, leave it as 25π cm225\pi\text{ cm}^225π cm2.
Finding the volume of a prism
A prism has the same cross-section throughout its length. Its volume is:
V=area of cross-section×length V=\text{area of cross-section}\times\text{length} V=area of cross-section×lengthThe cross-section is the repeated end face. It might be a rectangle, triangle, trapezium or another shape. This means a prism question often contains two stages: find the cross-sectional area, then multiply it by the prism's length.
Worked example: triangular prism
A triangular prism has a triangular cross-section with base 8 cm8\text{ cm}8 cm and perpendicular height 5 cm5\text{ cm}5 cm. The prism is 12 cm12\text{ cm}12 cm long.
First find the triangular cross-section's area:
A=12×8×5 A=\frac{1}{2}\times8\times5 A=21×8×5 A=20 cm2 A=20\text{ cm}^2 A=20 cm2Then multiply by the prism's length:
V=20×12 V=20\times12 V=20×12 V=240 cm3 V=240\text{ cm}^3 V=240 cm3Volume uses cubic units because it measures three-dimensional space. A cuboid is also a prism, so its familiar formula follows the same idea:
V=lwh V=lwh V=lwhThe rectangular cross-section has area lwlwlw, which is then multiplied by the remaining dimension hhh.
Units can earn or lose marks
Before calculating, check that every measurement uses the same unit. You should not multiply a length in metres by a width in centimetres without converting one of them.
Useful conversions include:
1 m=100 cm 1\text{ m}=100\text{ cm} 1 m=100 cmFor area, the conversion factor is squared:
1 m2=10,000 cm2 1\text{ m}^2=10{,}000\text{ cm}^2 1 m2=10,000 cm2For volume, it is cubed:
1 m3=1,000,000 cm3 1\text{ m}^3=1{,}000{,}000\text{ cm}^3 1 m3=1,000,000 cm3This is why converting units before applying the formula is often safer. If a rectangle measures 2 m2\text{ m}2 m by 50 cm50\text{ cm}50 cm, convert 50 cm50\text{ cm}50 cm to 0.5 m0.5\text{ m}0.5 m first. Its area is then:
A=2×0.5=1 m2 A=2\times0.5=1\text{ m}^2 A=2×0.5=1 m2A quick unit check is:
- perimeter and circumference: mm\text{mm}mm, cm\text{cm}cm or m\text{m}m
- area: mm2\text{mm}^2mm2, cm2\text{cm}^2cm2 or m2\text{m}^2m2
- volume: mm3\text{mm}^3mm3, cm3\text{cm}^3cm3 or m3\text{m}^3m3
Common mistakes in area and volume GCSE questions
Confusing perimeter with area
Underline the measurement requested. Words such as around, border and edge usually suggest perimeter. Words such as surface, cover and inside usually suggest area.
Using diameter as the radius
The circle area formula is A=πr2A=\pi r^2A=πr2. If the diagram gives a diameter, halve it before substituting.
Forgetting to square the radius
In πr2\pi r^2πr2, square only the radius. For r=4r=4r=4, the calculation is π×42=16π\pi\times4^2=16\piπ×42=16π, not (4π)2(4\pi)^2(4π)2.
Choosing a sloping height
Triangle and trapezium formulas require a perpendicular height. Search for a right angle rather than choosing the longest visible line.
Finding only the cross-sectional area
In a prism question, cross-sectional area is an intermediate answer. Multiply it by the prism's length to obtain volume.
Mixing measurements before converting
Write all dimensions in one unit before calculation. This keeps both the arithmetic and the final unit consistent.
Rounding too soon
Keep the calculator value on screen and round once, at the end, to the accuracy requested.
A practical revision method for resit students
Formula knowledge improves when recall and application are practised separately. Start with a blank sheet and write the formulas from memory. Then check them. Next, complete a mixed set without being told which formula belongs to each question.
That second stage matters because an exam does not usually announce, “Use the trapezium formula now.” Recognition is part of the task.
Use the MathsGenie Area and Perimeter revision guide when a method feels uncertain. Follow it with GCSE Area and Perimeter practice, where lessons, exam-style questions and worked solutions can turn a remembered formula into a reliable exam skill.
When you mark your work, record the reason for each error: wrong formula, wrong measurement, unit conversion, calculator entry or rounding. The mark scheme then becomes more than a score. It shows which habit needs repairing.
Past papers and predicted papers are most useful after topic practice. Work under timed conditions, show every substitution and use video solutions or mark schemes to investigate lost marks. A revision planner can space these sessions across the week, while mini tests reveal whether yesterday's method can still be recalled today.
Make the formulas dependable
Geometry becomes less intimidating when every question is reduced to a few decisions. What is being measured? Which shape or cross-section matters? Are the dimensions in matching units? What should the final unit be?
Write the formula, substitute the values and keep enough working for someone else to follow. That routine will not make every diagram look easy immediately, but it makes your response controlled. For a resit student, control is valuable: it turns familiar knowledge into marks.
Start with a MathsGenie Area and Perimeter lesson, practise the methods without notes, and finish with exam-style questions and mark schemes. Small, repeated successes are how formulas stop feeling like facts to remember and start becoming tools you know how to use.



