Magnetic fields (A-level only)

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Question 78
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When a proton moves at a speed vvv perpendicular to a uniform magnetic field of flux density BBB, the radius of its circular path is RRR.

A second proton moves at a speed 3v3v3v perpendicular to a uniform magnetic field of flux density 2B2B2B.

What is the radius of the path of the second proton?

23R\frac{2}{3}R32​R

32R\frac{3}{2}R23​R

6R6R6R

16R\frac{1}{6}R61​R

Magnetic fields (A-level only) Questions

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