The events A and B are such that P(A)=320\displaystyle P(A) = \frac{3}{20}P(A)=203, P(A∩B)=120\displaystyle P(A \cap B) = \frac{1}{20}P(A∩B)=201, P(A∣B)=514\displaystyle P(A|B) = \frac{5}{14}P(A∣B)=145. Find
P(B)P(B)P(B)
P(A∪B)P(A \cup B)P(A∪B)
P(B∣A′)P(B|A')P(B∣A′)
