The events A A\,A and B B\,B are such that P(A)=1120\displaystyle P(A) = \frac{11}{20}P(A)=2011, P(A∩B)=320\displaystyle P(A \cap B) = \frac{3}{20}P(A∩B)=203, P(A∣B)=38\displaystyle P(A|B) = \frac{3}{8}P(A∣B)=83. Find
P(B)P(B)P(B)
P(A∪B)P(A \cup B)P(A∪B)
P(B∣A′)P(B|A')P(B∣A′)
