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Conditional Probability

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Question 34

The events X X\,X and Y Y\,Y are such that P(X)=0.6P(X) = 0.6P(X)=0.6, P(X∩Y)=0.12P(X \cap Y) = 0.12P(X∩Y)=0.12 and P(X∣Y)=0.3P(X|Y) = 0.3P(X∣Y)=0.3.

a.

Find P(Y)P(Y)P(Y).

[3]
b.

Find P(X∪Y)P(X \cup Y)P(X∪Y).

[3]
c.

Find P(Y∣X′)P(Y|X')P(Y∣X′).

[3]

Conditional Probability Questions

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