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Conditional Probability

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Question 20

The events E E\,E and F F\,F are such that P(E)=0.2P(E) = 0.2P(E)=0.2 and P(E∪F)=0.6P(E \cup F) = 0.6P(E∪F)=0.6.

a.

Find P(E′∩F′)P(E' \cap F')P(E′∩F′).

[2]
b.

Find P(E′∩F)P(E' \cap F)P(E′∩F).

[2]
c.

Given also that the events E E\,E and F F\,F are independent, find P(F)P(F)P(F).

[4]
d.

Find P(E′∪F′)P(E' \cup F')P(E′∪F′).

[2]

Conditional Probability Questions

  1. A Level
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  3. /Conditional Probability