The random variable X X\,X has the distribution X∼B(12,p)X \sim B(12, p)X∼B(12,p), and P(X=0)=0.0687P(X = 0) = 0.0687P(X=0)=0.0687 to 3 significant figures.
Show that p=0.2p = 0.2p=0.2.
Hence find P(X≥3)P(X \ge 3)P(X≥3).
Find P(X=1)P(X=1)P(X=1).