A box contains $n\,$ red counters and 6 blue counters, where $n\,$ is a positive integer. Two counters are taken from the box at random, without replacement.

The probability that both counters taken are blue is $18\displaystyle \frac{1}{8}$ .

Show that $n^2 + 11n - 210 = 0$ .

Hence find the value of $n$ .

Find the probability that the two counters taken are different colours.

A box contains $n\,$ red counters and 6 blue counters, where $n\,$ is a positive integer. Two counters are taken from the box at random, without replacement.

The probability that both counters taken are blue is $18\displaystyle \frac{1}{8}$ .

Show that $n^2 + 11n - 210 = 0$ .

Hence find the value of $n$ .

Find the probability that the two counters taken are different colours.

2 Statistics

Question 28

Markscheme

2 Statistics

Question 28

Markscheme

2 Statistics

Question 28

2 Statistics Questions

2 Statistics

Question 28

2 Statistics Questions