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2 Statistics

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Question 189

The random variable X X\,X has the distribution X∼B(6,0.35)X\sim B(6,0.35)X∼B(6,0.35).

One term in the expansion of (0.65+0.35)6(0.65+0.35)^6(0.65+0.35)6 is (62)(0.65)4(0.35)2\binom62(0.65)^4(0.35)^2(26​)(0.65)4(0.35)2.

a.

State the probability involving X X\,X that this term represents.

[1]
b.

Explain why the sum of all seven terms in the expansion is equal to the sum of the probabilities P(X=r)P(X=r)P(X=r) for r=0,1,…,6r=0,1,\ldots,6r=0,1,…,6.

[2]
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2 Statistics Questions

  1. A Level
  2. /Maths
  3. /2 Statistics

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