The random variable X X\,X has the distribution X∼B(6,0.35)X\sim B(6,0.35)X∼B(6,0.35).
One term in the expansion of (0.65+0.35)6(0.65+0.35)^6(0.65+0.35)6 is (62)(0.65)4(0.35)2\binom62(0.65)^4(0.35)^2(26)(0.65)4(0.35)2.
State the probability involving X X\,X that this term represents.
Explain why the sum of all seven terms in the expansion is equal to the sum of the probabilities P(X=r)P(X=r)P(X=r) for r=0,1,…,6r=0,1,\ldots,6r=0,1,…,6.