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2.3 Probability

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Question 72

A precision industrial laser's cooling system maintains a temperature deviation TTT, measured in millikelvins (mK) from a reference point. The random variable T T\,T follows a continuous distribution with cumulative distribution function F(t)F(t)F(t). The graph of F(t)F(t)F(t) consists of a single straight line segment from the point (−5,0)(-5, 0)(−5,0) to the point (15,1)(15, 1)(15,1). For t<−5t < -5t<−5, F(t)=0F(t) = 0F(t)=0, and for t>15t > 15t>15, F(t)=1F(t) = 1F(t)=1.

a.

Specify fully the probability density function f(t)f(t)f(t) of TTT.

[2]
b.

Write down the value of E(T)E(T)E(T).

[1]
c.

Determine the value of k k\,k such that P(2.5≤T≤k)=0.35P(2.5 \le T \le k) = 0.35P(2.5≤T≤k)=0.35.

[2]
d.

One operating hour is selected at random.

Calculate the probability that the temperature deviation is between 6 mK and 10 mK.

[2]
e.

Given that the temperature deviation was between 6 mK and 10 mK, calculate the probability that it was greater than 9.1 mK.

[3]
f.

A random sample of 40 operating hours is taken.

Calculate the probability that for at most 5 of these hours the temperature deviation is between 6 mK and 10 mK.

[3]

2.3 Probability Questions

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