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2.3 Probability

2.3 Probability

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Question 2
55%

The events A A\,A and B B\,B are such that P(A)=14\displaystyle P(A) = \frac{1}{4}P(A)=41​, P(A∩B)=110\displaystyle P(A \cap B) = \frac{1}{10}P(A∩B)=101​ and P(A∣B)=25\displaystyle P(A|B) = \frac{2}{5}P(A∣B)=52​.

a.

Find P(B)P(B)P(B).

[3]
b.

Find P(A∪B)P(A \cup B)P(A∪B).

[3]
c.

Find P(B∣A′)P(B|A')P(B∣A′).

[3]
Markscheme

2.3 Probability Questions

  1. A Level
  2. /Maths
  3. /2.3 Probability

200 exam-style questions on OCR A Level Maths 2.3 Probability, covering 2.3.1 Mutually exclusive and independent events, 2.3.2 Diagrams to assist probability calculations, 2.3.3 Conditional probability (A-level only), 2.3.4 Conditional probability from first principles (A-level only), and 2.3.5 Modelling with probability. Each one has a worked solution and a mark scheme showing where the marks go.

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