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2.3 Probability

2.3 Probability

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Question 53

The events A and B are such that P(A)=320\displaystyle P(A) = \frac{3}{20}P(A)=203​, P(A∩B)=120\displaystyle P(A \cap B) = \frac{1}{20}P(A∩B)=201​, P(A∣B)=514\displaystyle P(A|B) = \frac{5}{14}P(A∣B)=145​. Find

a.

P(B)P(B)P(B)

[3]
b.

P(A∪B)P(A \cup B)P(A∪B)

[3]
c.

P(B∣A′)P(B|A')P(B∣A′)

[3]
Markscheme

2.3 Probability Questions

  1. A Level
  2. /Maths
  3. /2.3 Probability

200 exam-style questions on OCR A Level Maths 2.3 Probability, covering 2.3.1 Mutually exclusive and independent events, 2.3.2 Diagrams to assist probability calculations, 2.3.3 Conditional probability (A-level only), 2.3.4 Conditional probability from first principles (A-level only), and 2.3.5 Modelling with probability. Each one has a worked solution and a mark scheme showing where the marks go.

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