Show that the equation
10cosθ=3cosecθ 10 \cos \theta = 3 \operatorname{cosec} \theta 10cosθ=3cosecθcan be written in the form
sin2θ=k \sin 2\theta = k sin2θ=kwhere kkk is a constant to be found.
Hence find the smallest positive solution of the equation
10cosθ=3cosecθ 10 \cos \theta = 3 \operatorname{cosec} \theta 10cosθ=3cosecθgiving your answer, in degrees, to one decimal place.