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Question 1
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Solve, for
−180≤x≤180-180 \leq x \leq 180
−
180
≤
x
≤
180
, the equation,
cos2x+5sinx+2=0 \cos 2x + 5 \sin x + 2 = 0
cos
2
x
+
5
sin
x
+
2
=
0
[5]
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Trigonometry and Modelling Questions
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