Solve, for −π<x<π-\pi < x < \pi−π<x<π, the equation 4cos(2x−0.3)+1=04\cos(2x - 0.3) + 1 = 04cos(2x−0.3)+1=0 giving your answers, in radians, to 2 decimal places.
Solve, for 0∘<θ<360∘0^\circ < \theta < 360^\circ0∘<θ<360∘, the equation 3tanθsinθ=8−cosθ3\tan \theta \sin \theta = 8 - \cos \theta3tanθsinθ=8−cosθ giving your answers, in degrees, to one decimal place.