Trigonometry and Modelling

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Question 25
Medium
a.

A robotic arm's joint efficiency factor EEE is modelled by the formula E=cot⁡β−tan⁡βE = \cot \beta - \tan \betaE=cotβ−tanβ, where β\betaβ is the angle of the joint. Prove that for sin⁡2β≠0\sin 2\beta \neq 0sin2β=0,

cot⁡β−tan⁡β=2cot⁡2β\cot \beta - \tan \beta = 2 \cot 2\betacotβ−tanβ=2cot2β

[4]
b.

Explain why the identity cot⁡β−tan⁡β=2cot⁡2β\cot \beta - \tan \beta = 2 \cot 2\betacotβ−tanβ=2cot2β is not valid when sin⁡β=0\sin \beta = 0sinβ=0.

[2]

Trigonometry and Modelling Questions

  1. A Level
  2. /Maths
  3. /Trigonometry and Modelling