Energetics

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Question 26
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Hydrazine (N2H4\text{N}_2\text{H}_4N2​H4​) is a highly reactive liquid used as a rocket propellant. Direct measurement of its standard enthalpy of formation is difficult, but it can be determined using Hess's law and standard enthalpies of combustion:

N2H4(l)+O2(g)→N2(g)+2H2O(l)ΔH⊖=−622 kJ mol−1 \text{N}_2\text{H}_4(\text{l}) + \text{O}_2(\text{g}) \rightarrow \text{N}_2(\text{g}) + 2\text{H}_2\text{O}(\text{l}) \quad \Delta H^\ominus = -622\text{ kJ mol}^{-1} N2​H4​(l)+O2​(g)→N2​(g)+2H2​O(l)ΔH⊖=−622 kJ mol−1 H2(g)+12O2(g)→H2O(l)ΔH⊖=−286 kJ mol−1 \text{H}_2(\text{g}) + \frac{1}{2}\text{O}_2(\text{g}) \rightarrow \text{H}_2\text{O}(\text{l}) \quad \Delta H^\ominus = -286\text{ kJ mol}^{-1} H2​(g)+21​O2​(g)→H2​O(l)ΔH⊖=−286 kJ mol−1

What is the standard enthalpy of formation of liquid hydrazine (in kJ mol−1\text{kJ mol}^{-1}kJ mol−1), as represented by the following equation?

N2(g)+2H2(g)→N2H4(l) \text{N}_2(\text{g}) + 2\text{H}_2(\text{g}) \rightarrow \text{N}_2\text{H}_4(\text{l}) N2​(g)+2H2​(g)→N2​H4​(l)

+336+336+336

+50+50+50

−50-50−50

−1194-1194−1194

Energetics Questions

  1. A Level
  2. /Chemistry
  3. /Energetics