Energetics

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Question 14
Medium
1.

Define the term mean bond enthalpy.

[2]
2.

Hydrazine (N2H4\text{N}_2\text{H}_4N2​H4​) is used as a rocket propellant that is oxidised by hydrogen peroxide (H2O2\text{H}_2\text{O}_2H2​O2​) in the gas phase according to the equation:

N2H4(g)+2H2O2(g)→N2(g)+4H2O(g) \text{N}_2\text{H}_4(g) + 2\text{H}_2\text{O}_2(g) \rightarrow \text{N}_2(g) + 4\text{H}_2\text{O}(g) N2​H4​(g)+2H2​O2​(g)→N2​(g)+4H2​O(g)

The enthalpy change for this reaction is ΔH=−795 kJ mol−1\Delta H = -795\text{ kJ mol}^{-1}ΔH=−795 kJ mol−1.

Table 1 shows some mean bond enthalpy values:

BondMean bond enthalpy / kJ mol−1\text{kJ mol}^{-1}kJ mol−1
N−H\text{N}-\text{H}N−H391
O−O\text{O}-\text{O}O−O144
N≡N\text{N}\equiv\text{N}N≡N945
O−H\text{O}-\text{H}O−H463

Use the data in Table 1 to calculate a value for the N−N\text{N}-\text{N}N−N bond enthalpy in hydrazine.

[4]

Energetics Questions

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