The molar enthalpy of vaporisation (ΔHvap\Delta H_{\text{vap}}ΔHvap) of a liquid is the enthalpy change when one mole of liquid is converted to vapour at its boiling point.
A chemist performs an experiment to determine ΔHvap\Delta H_{\text{vap}}ΔHvap for tetrachloromethane (CCl4\text{CCl}_4CCl4).
The chemist:
The mass of tetrachloromethane vaporised and lost from the flask during this period is 1.31 kg1.31\text{ kg}1.31 kg.
Calculate the molar enthalpy of vaporisation, ΔHvap\Delta H_{\text{vap}}ΔHvap, for tetrachloromethane in kJ mol−1\text{kJ mol}^{-1}kJ mol−1.
(Molar mass of CCl4=154.0 g mol−1\text{CCl}_4 = 154.0\text{ g mol}^{-1}CCl4=154.0 g mol−1)
[1 kW=1 kJ s−1][1\text{ kW} = 1\text{ kJ s}^{-1}][1 kW=1 kJ s−1]