Energetics

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Question 8
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Anhydrous magnesium sulfate, MgSO4\text{MgSO}_4MgSO4​, can absorb water to form the hydrated salt magnesium sulfate heptahydrate, MgSO4⋅7H2O\text{MgSO}_4\cdot 7\text{H}_2\text{O}MgSO4​⋅7H2​O.

MgSO4(s)+7H2O(l)→MgSO4⋅7H2O(s)\text{MgSO}_4(\text{s}) + 7\text{H}_2\text{O}(\text{l}) \rightarrow \text{MgSO}_4\cdot 7\text{H}_2\text{O}(\text{s})MgSO4​(s)+7H2​O(l)→MgSO4​⋅7H2​O(s)

Hess's Law Cycle

a.

Suggest one reason why the enthalpy change for this reaction cannot be determined directly by calorimetry.

[1]
b.

Some enthalpies of solution are shown in the table below:

SaltEnthalpy of solution / kJ mol−1\text{kJ mol}^{-1}kJ mol−1
MgSO4(s)\text{MgSO}_4(\text{s})MgSO4​(s)−91.2-91.2−91.2
MgSO4⋅7H2O(s)\text{MgSO}_4\cdot 7\text{H}_2\text{O}(\text{s})MgSO4​⋅7H2​O(s)+15.9+15.9+15.9

Calculate the enthalpy change for the hydration of anhydrous magnesium sulfate to form magnesium sulfate heptahydrate.

[3]

Energetics Questions

  1. A Level
  2. /Chemistry
  3. /Energetics