Energetics

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Question 22
Medium

Anhydrous cobalt(II) chloride, CoCl2\text{CoCl}_2CoCl2​, is a blue solid that hydrates in the presence of water to form a pink hexahydrate, CoCl2⋅6H2O\text{CoCl}_2\cdot 6\text{H}_2\text{O}CoCl2​⋅6H2​O.

CoCl2(s)+6H2O(l)→CoCl2⋅6H2O(s)\text{CoCl}_2(\text{s}) + 6\text{H}_2\text{O}(\text{l}) \rightarrow \text{CoCl}_2\cdot 6\text{H}_2\text{O}(\text{s})CoCl2​(s)+6H2​O(l)→CoCl2​⋅6H2​O(s)

a.

Explain why it is not possible to measure the enthalpy change for this reaction directly using a simple cup calorimeter.

[1]
b.

The enthalpies of solution for the anhydrous and hydrated cobalt(II) chloride salts are given in the table below:

SubstanceEnthalpy of solution / kJ mol−1\text{kJ mol}^{-1}kJ mol−1
CoCl2(s)\text{CoCl}_2(\text{s})CoCl2​(s)−82.4-82.4−82.4
CoCl2⋅6H2O(s)\text{CoCl}_2\cdot 6\text{H}_2\text{O}(\text{s})CoCl2​⋅6H2​O(s)+3.8+3.8+3.8

By constructing an appropriate Hess's Law cycle, calculate the standard enthalpy change for the hydration of anhydrous cobalt(II) chloride to form the hexahydrate salt.

[3]

Energetics Questions

  1. A Level
  2. /Chemistry
  3. /Energetics