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Energetics

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Question 6

In an experiment to investigate the heat energy released during a neutralization reaction, a student records the following results:

  • Volume of dilute nitric acid solution = 40.0 cm340.0\text{ cm}^340.0 cm3
  • Volume of potassium hydroxide solution = 60.0 cm360.0\text{ cm}^360.0 cm3
  • Initial temperature of both solutions = 19.4∘C19.4^\circ\text{C}19.4∘C
  • Highest temperature reached by the mixture = 28.1∘C28.1^\circ\text{C}28.1∘C

Calculate the heat energy released, in joules (J\text{J}J), using the equation:

Q=m×4.18×ΔT Q = m \times 4.18 \times \Delta T Q=m×4.18×ΔT

where:

  • QQQ is the heat energy released in J\text{J}J
  • mmm is the mass of the mixture in g\text{g}g
  • ΔT\Delta TΔT is the change in temperature in ∘C^\circ\text{C}∘C

Assume that the density of the mixture is 1.04 g cm−31.04\text{ g cm}^{-3}1.04 g cm−3, so the mass of 1.00 cm31.00\text{ cm}^31.00 cm3 of the mixture is 1.04 g1.04\text{ g}1.04 g. Give your answer to 3 significant figures.

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Markscheme

Energetics Questions

  1. IGCSE
  2. /Chemistry
  3. /Energetics

35 exam-style questions on Edexcel IGCSE Chemistry Energetics. Each one has a worked solution and a mark scheme showing where the marks go.

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