Skip to content
MathsGenie logo
Quick links
Open app

Course home

  1. IGCSE
  2. Chemistry Edexcel
  3. Question bank

Energetics

MediumHard
12345678910111213141516171819202122232425262728293031323334353637383940
Question 16

A student designed an experiment to measure the temperature change when magnesium ribbon is added to dilute hydrochloric acid. Their experimental plan was as follows:

  • Measure 80 cm380\text{ cm}^380 cm3 of dilute hydrochloric acid and pour it into a polystyrene cup.
  • Record the initial temperature of the acid solution.
  • Add 0.45 g0.45\text{ g}0.45 g of magnesium ribbon, stir the mixture, and record the maximum temperature reached.

The student's recorded data is shown below:

  • Volume of hydrochloric acid solution = 80 cm380\text{ cm}^380 cm3
  • Mass of magnesium ribbon = 0.45 g0.45\text{ g}0.45 g
  • Starting temperature = 21.8∘C21.8^\circ\text{C}21.8∘C
  • Maximum temperature reached = 39.4∘C39.4^\circ\text{C}39.4∘C
a.

Why is it better to use a polystyrene cup rather than a metal beaker for this experiment?

[1]
b.

The chemical equation for this reaction is:

Mg(s)+2HCl(aq)→MgCl2(aq)+H2(g) \text{Mg}(s) + 2\text{HCl}(aq) \rightarrow \text{MgCl}_2(aq) + \text{H}_2(g) Mg(s)+2HCl(aq)→MgCl2​(aq)+H2​(g)

Suggest one observation, other than the change in temperature, that could be made during this reaction.

[1]
c.

State whether this reaction is exothermic or endothermic, and justify your response.

[2]
d.

Calculate the heat energy change (in Joules) in this experiment using the expression:

heat energy change=volume of solution×4.2×temperature change \text{heat energy change} = \text{volume of solution} \times 4.2 \times \text{temperature change} heat energy change=volume of solution×4.2×temperature change
[2]

Energetics Questions

  1. IGCSE
  2. /Chemistry
  3. /Energetics