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Energetics

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Question 30

In an experiment to investigate the heat energy released during a neutralization reaction, a student records the following results:

  • Volume of sodium hydroxide solution = 50.0 cm3
  • Starting temperature of sodium hydroxide solution = 16.5∘C16.5^\circ\text{C}16.5∘C
  • Total volume of hydrochloric acid added = 50.0 cm3
  • Highest temperature reached by the mixture = 31.5∘C31.5^\circ\text{C}31.5∘C

Calculate the heat energy released, in joules (J\text{J}J), using the equation:

Q=m×4.18×ΔT Q = m \times 4.18 \times \Delta T Q=m×4.18×ΔT

where:

  • Q Q\,Q is the heat energy released in J\text{J}J
  • m m\,m is the mass of the mixture in g\text{g}g
  • ΔT \Delta T\,ΔT is the change in temperature in ∘C^\circ\text{C}∘C

Assume that the mass of 1.00 cm3 of the mixture is 1.00 g.

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Energetics Questions

  1. IGCSE
  2. /Chemistry
  3. /Energetics