A hairdryer is connected to the 230 V mains supply.
The current in the hairdryer is 5.0 A.
Write down the equation that links power, potential difference and current.
Calculate the power of the hairdryer.
The hairdryer is used for 4.0 minutes.
Calculate the energy transferred by the hairdryer.
Give your answer in kJ\text{kJ}kJ.
Use your answer to (c) and the equation: energy transferred=charge×potential difference\text{energy transferred} = \text{charge} \times \text{potential difference}energy transferred=charge×potential difference
Calculate the charge that flows through the hairdryer in 4.0 minutes.
42 exam-style questions on OCR GCSE Physics 3.2 Simple circuits, covering 3.2.1 Series and parallel circuits, 3.2.2 Circuit symbols and circuit diagrams, 3.2.3 Current, potential difference and resistance, 3.2.4 Ohm's law, 3.2.5 Ohmic and non-ohmic resistors, 3.2.6 Designing circuits to investigate resistance, 3.2.7 Linear and non-linear circuit components, 3.2.8 Current-potential difference graphs for components, 3.2.9 Resistance in series and parallel, 3.2.10 Series and parallel circuit problems, 3.2.11 Circuits for measurement and testing, 3.2.12 Power transfer in circuit devices, and 3.2.13 Energy and power in resistor circuits. Each one has a worked solution and a mark scheme showing where the marks go.