A student connects a resistor to a 6.0 V battery.
The current in the resistor is 0.25 A.
Use the equation: potential difference=current×resistance\text{potential difference} = \text{current} \times \text{resistance}potential difference=current×resistance
Calculate the resistance of the resistor.
The student replaces the battery with a 12 V battery. The resistance of the resistor stays the same.
State the new current in the resistor. Give a reason for your answer.
State what is meant by potential difference.
The student keeps the potential difference at 12 V but uses a resistor with a larger resistance.
Describe what happens to the current.
42 exam-style questions on OCR GCSE Physics 3.2 Simple circuits, covering 3.2.1 Series and parallel circuits, 3.2.2 Circuit symbols and circuit diagrams, 3.2.3 Current, potential difference and resistance, 3.2.4 Ohm's law, 3.2.5 Ohmic and non-ohmic resistors, 3.2.6 Designing circuits to investigate resistance, 3.2.7 Linear and non-linear circuit components, 3.2.8 Current-potential difference graphs for components, 3.2.9 Resistance in series and parallel, 3.2.10 Series and parallel circuit problems, 3.2.11 Circuits for measurement and testing, 3.2.12 Power transfer in circuit devices, and 3.2.13 Energy and power in resistor circuits. Each one has a worked solution and a mark scheme showing where the marks go.