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Question 18
Easy

A student calculates acceleration using this equation:

(final velocity)2−(initial velocity)2=2×acceleration×distance (\text{final velocity})^2 - (\text{initial velocity})^2 = 2 \times \text{acceleration} \times \text{distance} (final velocity)2−(initial velocity)2=2×acceleration×distance

What is the correct equation for acceleration?

acceleration=(final velocity)2−(initial velocity)2−2×distance\text{acceleration} = (\text{final velocity})^2 - (\text{initial velocity})^2 - 2 \times \text{distance}acceleration=(final velocity)2−(initial velocity)2−2×distance

acceleration=(final velocity)2−(initial velocity)22×distance\text{acceleration} = \frac{(\text{final velocity})^2 - (\text{initial velocity})^2}{2 \times \text{distance}}acceleration=2×distance(final velocity)2−(initial velocity)2​

acceleration=2×distance×((final velocity)2−(initial velocity)2)\text{acceleration} = 2 \times \text{distance} \times ((\text{final velocity})^2 - (\text{initial velocity})^2)acceleration=2×distance×((final velocity)2−(initial velocity)2)

acceleration=2×distance(final velocity)2−(initial velocity)2\text{acceleration} = \frac{2 \times \text{distance}}{(\text{final velocity})^2 - (\text{initial velocity})^2}acceleration=(final velocity)2−(initial velocity)22×distance​

Motion Questions

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