A skateboarder starts at an initial velocity of 0.0 m/s and accelerates at 1.5 m/s2 for a distance of 25 m.
What is the final velocity of the skateboarder?
Use the equation: (final velocity)2−(initial velocity)2=2×acceleration×distance\text{(final velocity)}^2 - \text{(initial velocity)}^2 = 2 \times \text{acceleration} \times \text{distance}(final velocity)2−(initial velocity)2=2×acceleration×distance
6.1 m/s6.1\text{ m/s}6.1 m/s
8.7 m/s8.7\text{ m/s}8.7 m/s
37.5 m/s37.5\text{ m/s}37.5 m/s
75 m/s75\text{ m/s}75 m/s
50 exam-style questions on OCR GCSE Physics Motion. Each one has a worked solution and a mark scheme showing where the marks go.