b226-1ed9-4b6e-9b49-cbd631b12342","revisionId":"21186d4d-9f25-4a7d-949d-907142b658fe","questionNumber":null,"questionType":"LA","specification":"An experimental glider is released from rest at the top of an inclined air track.\n\nThe distance from the starting position of the glider to the light gate located near the bottom of the track is \$1.8\\text{ m}\$.\n\nThe speed of the glider as it passes through the light gate is recorded as \$3.15\\text{ m/s}\$.","difficulty":4,"difficultyBand":"medium","totalMarks":6,"sourceTitle":null,"calculatorUse":null,"parts":[{"id":"6e5bbfac-16b8-49a0-92fc-2233329190bd","label":"a","content":"Calculate the acceleration of the glider as it moves down the track. Give your answer to 2 decimal places.","markscheme":"- States or uses $v^2 = u^2 + 2as$ with $u = 0$ M1\n- Substitutes the given values to rearrange for acceleration: $a = \\frac{3.15^2}{2 \\times 1.8}$ M1\n- Obtains $a \\approx 2.76$ $\\text{m/s}^2$ A1","marks":3,"order":0,"markingRubric":null,"explanation":{"methods":[{"id":"kinematics_equation","label":"Use the motion equation","steps":[{"type":"text","order":1,"title":"Choose the equation","content":"Use the SUVAT equation that links final speed, initial speed, acceleration and distance:\n\n$$v^2=u^2+2as$$\n\nThe glider is released from rest, so $u=0\\text{ m/s}$. From the question, $v=3.15\\text{ m/s}$ and $s=1.8\\text{ m}$.\n\nUsing this equation and recognising that $u=0$ because the glider is released from rest earns M1.","highlights":[{"text":"released from rest","location":"specification"},{"text":"The distance from the starting position of the glider to the light gate located near the bottom of the track is \$1.8\\text{ m}\$.","location":"specification"},{"text":"The speed of the glider as it passes through the light gate is recorded as \$3.15\\text{ m/s}\$.","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"\\htmlData{anchor=original}{v^2=u^2+2as}"},{"latex":"\\htmlData{anchor=substituted}{(3.15)^2=0^2+2a(1.8)}"},{"latex":"\\htmlData{anchor=rearranged}{a=\\frac{(3.15)^2}{2(1.8)}}"}],"highlights":[{"color":"green","style":"box","anchor":"rearranged"}],"connections":[{"to":"substituted","from":"original","color":"sky","label":"substitute"},{"to":"rearranged","from":"substituted","color":"orange","label":"rearrange"}]},"order":2,"title":"Substitute and rearrange","description":"Substitute the measured final speed, zero initial speed and distance, then rearrange to make acceleration the subject. This substitution and rearrangement earns M1."},{"type":"text","order":6,"title":"Calculate and round","content":"Now evaluate the expression: $$a=\\frac{3.15^2}{2\\times1.8}=2.75625\\ \\text{m/s}^2.$$ To 2 decimal places, the acceleration is $$\\boxed{a=2.76\\ \\text{m/s}^2}.$$ The unit is $\\text{m/s}^2$ because acceleration measures change in velocity per second; this final value earns the accuracy mark (A1)."}]}],"generatedAt":"2026-07-22T11:37:23.102Z","modelVersion":"gpt-5.6-terra+diagrams-1","explanationVersion":"v3"},"options":[]},{"id":"b4cf62d7-6581-404b-af94-edd5c26e8f51","label":"b","content":"The glider has a mass of \$0.85\\text{ kg}\$. Calculate its kinetic energy as it passes through the light gate. Give your answer to 2 decimal places.","markscheme":"- States or uses $E_k = \\frac{1}{2}mv^2$ M1\n- Substitutes $m = 0.85$ and $v = 3.15$ to get $E_k = \\frac{1}{2} \\times 0.85 \\times 3.15^2$ M1\n- Obtains $E_k \\approx 4.22$ $\\text{J}$ A1","marks":3,"order":1,"markingRubric":null,"explanation":{"methods":[{"id":"kinetic_energy","label":"Use the kinetic energy formula","steps":[{"type":"text","order":1,"title":"Choose the formula","content":"Use the kinetic energy equation $$E_k=\\frac{1}{2}mv^2.$$ At the light gate, use $m=0.85\\text{ kg}$ and $v=3.15\\text{ m/s}$. The $1.8\\text{ m}$ distance is not needed for this calculation. Writing the correct formula earns the first M1.","highlights":[{"text":"The glider has a mass of \\(0.85\\text{

Motion

Question 27

Motion Questions

Motion

Question 27

Motion Questions