A car is travelling along a straight road at 25 m/s. The driver brakes and the car decelerates uniformly. The car stops in a distance of 50 m.
Use the equation: (final velocity)2−(initial velocity)2=2×acceleration×distance(\text{final velocity})^2 - (\text{initial velocity})^2 = 2 \times \text{acceleration} \times \text{distance}(final velocity)2−(initial velocity)2=2×acceleration×distance
Calculate the deceleration of the car.
Calculate the time taken for the car to stop.
The same car travels at 50 m/s and brakes with the same deceleration.
Explain why the distance the car travels while braking is now four times larger.
43 exam-style questions on OCR GCSE Physics 2.1 Motion, covering 2.1.1 Measuring distance and time, 2.1.2 Measuring speed, 2.1.3 Ratios, units and rates in motion, 2.1.4 Scalars and vectors in motion, 2.1.5 Distance-time and velocity-time graphs, 2.1.6 Area under a velocity-time graph, 2.1.7 Average speed for non-uniform motion, and 2.1.8 Uniform motion and uniform acceleration. Each one has a worked solution and a mark scheme showing where the marks go.