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Iteration

Iteration

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Question 8

Using xn+1=12xn2+3\displaystyle x_{n+1} = \frac{12}{x_n^2 + 3}xn+1​=xn2​+312​ with x0=1x_0 = 1x0​=1

Find the values of x1x_1x1​, x2 x_2\,x2​ and x3x_3x3​.

[3]
Markscheme

Iteration Questions

  1. GCSE
  2. /Maths
  3. /Iteration

124 exam-style questions on Eduqas GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.

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