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Iteration

Iteration

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Question 2
a.

Show that the equation x3+2x=1x^3 + 2x = 1x3+2x=1 has a solution between x=0x = 0x=0 and x=1x = 1x=1.

[2]
b.

Show that the equation x3+2x=1x^3 + 2x = 1x3+2x=1 can be rearranged to give: x=12−x32\displaystyle x = \frac{1}{2} - \frac{x^3}{2}x=21​−2x3​

[1]
c.

Starting with x0=0x_0 = 0x0​=0, use the iteration formula xn+1=12−xn32\displaystyle x_{n+1} = \frac{1}{2} - \frac{x_n^3}{2}xn+1​=21​−2xn3​​ twice to find an estimate for the solution to x3+2x=1x^3 + 2x = 1x3+2x=1

[3]
Markscheme

Iteration Questions

  1. GCSE
  2. /Maths
  3. /Iteration

124 exam-style questions on Eduqas GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.

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