Show that the equation x3+2x=1x^3 + 2x = 1x3+2x=1 has a solution between x=0x = 0x=0 and x=1x = 1x=1.
Show that the equation x3+2x=1x^3 + 2x = 1x3+2x=1 can be rearranged to give: x=12−x32\displaystyle x = \frac{1}{2} - \frac{x^3}{2}x=21−2x3
Starting with x0=0x_0 = 0x0=0, use the iteration formula xn+1=12−xn32\displaystyle x_{n+1} = \frac{1}{2} - \frac{x_n^3}{2}xn+1=21−2xn3 twice to find an estimate for the solution to x3+2x=1x^3 + 2x = 1x3+2x=1
124 exam-style questions on Eduqas GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.