The number of deer in a forest t t\,t years from now is Pt P_t\,Pt where
P0=1000 P_0 = 1000 P0=1000 Pt+1=1.02(Pt−80) P_{t+1} = 1.02(P_t - 80) Pt+1=1.02(Pt−80)Work out the number of deer in the forest 3 years from now.
124 exam-style questions on Eduqas GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.