Using xn+1=8xn2+4\displaystyle x_{n+1} = \frac{8}{x_n^2} + 4xn+1=xn28+4 with x0=4.5x_0 = 4.5x0=4.5
Find the values of x1x_1x1, x2 x_2\,x2 and x3x_3x3.
Explain the relationship between the values of x1x_1x1, x2 x_2\,x2 and x3 x_3\,x3 and the equation x3−4x2−8=0x^3 - 4x^2 - 8 = 0x3−4x2−8=0
Practise Eduqas GCSE Maths Iteration with exam-style questions for Foundation and Higher tier. 40 questions, matched to the Eduqas GCSE Maths (C300QS) specification and written in Component 1 and Component 2 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.