Show that the equation 9x3−x2−18=09x^3 - x^2 - 18 = 09x3−x2−18=0 has a solution between x=1x = 1x=1 and x=2x = 2x=2.
Show that the equation x=189x−1\displaystyle x = \sqrt{\frac{18}{9x - 1}}x=9x−118 can be rearranged to give: 9x3−x2−18=09x^3 - x^2 - 18 = 09x3−x2−18=0
Starting with x0=1x_0 = 1x0=1, use the iteration formula xn+1=189xn−1\displaystyle x_{n+1} = \sqrt{\frac{18}{9x_n - 1}}xn+1=9xn−118 twice to find an estimate for the solution to 9x3−x2−18=09x^3 - x^2 - 18 = 09x3−x2−18=0
124 exam-style questions on Eduqas GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.