Using xn+1=6xn+2\displaystyle x_{n+1} = \frac{6}{x_n + 2}xn+1=xn+26 with x0=2x_0 = 2x0=2
Find the values of x1x_1x1, x2 x_2\,x2 and x3x_3x3.
40 exam-style questions on AQA GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.