Using xn+1=6xn+2\displaystyle x_{n+1} = \frac{6}{x_n + 2}xn+1=xn+26 with x0=2x_0 = 2x0=2
Find the values of x1x_1x1, x2 x_2\,x2 and x3x_3x3.
Practise AQA GCSE Maths Iteration with exam-style questions for Foundation and Higher tier. 40 questions, matched to the AQA GCSE Maths (8300) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.