Using xn+1=2+7xn\displaystyle x_{n+1} = 2 + \frac{7}{x_n}xn+1=2+xn7 with x0=4x_0 = 4x0=4
Find the values of x1x_1x1, x2 x_2\,x2 and x3x_3x3.
Practise AQA GCSE Maths Iteration with exam-style questions for Foundation and Higher tier. 40 questions, matched to the AQA GCSE Maths (8300) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.