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Iteration

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Question 30
a.

Show that the equation x3+4x=1x^3 + 4x = 1x3+4x=1 has a solution between x=0x = 0x=0 and x=1x = 1x=1.

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b.

Show that the equation x3+4x=1x^3 + 4x = 1x3+4x=1 can be rearranged to give: x=14−x34\displaystyle x = \frac{1}{4} - \frac{x^3}{4}x=41​−4x3​

[1]
c.

Starting with x0=0x_0 = 0x0​=0, use the iteration formula xn+1=14−xn34\displaystyle x_{n+1} = \frac{1}{4} - \frac{x_n^3}{4}xn+1​=41​−4xn3​​ twice to find an estimate for the solution to x3+4x=1x^3 + 4x = 1x3+4x=1

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Markscheme

Iteration Questions

  1. GCSE
  2. /Maths
  3. /Iteration

40 exam-style questions on AQA GCSE Maths Iteration. Each one has a worked solution and a mark scheme showing where the marks go.

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