Show that the equation x3+5x=2x^3 + 5x = 2x3+5x=2 has a solution between x=0x = 0x=0 and x=1x = 1x=1.
Show that the equation x3+5x=2x^3 + 5x = 2x3+5x=2 can be rearranged to give: x=25−x35\displaystyle x = \frac{2}{5} - \frac{x^3}{5}x=52−5x3
Starting with x0=0x_0 = 0x0=0, use the iteration formula xn+1=25−xn35\displaystyle x_{n+1} = \frac{2}{5} - \frac{x_n^3}{5}xn+1=52−5xn3 twice to find an estimate for the solution to x3+5x=2x^3 + 5x = 2x3+5x=2.
Practise AQA GCSE Maths Iteration with exam-style questions for Foundation and Higher tier. 40 questions, matched to the AQA GCSE Maths (8300) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.