At equilibrium the forward rate is 4.0 mol min−14.0\,\mathrm{mol\,min^{-1}}4.0molmin−1. What is the reverse rate?
000
4.0 mol min−14.0\,\mathrm{mol\,min^{-1}}4.0molmin−1
2.0 mol min−12.0\,\mathrm{mol\,min^{-1}}2.0molmin−1
8.0 mol min−18.0\,\mathrm{mol\,min^{-1}}8.0molmin−1
45 exam-style questions on Edexcel GCSE Chemistry 5.2 Reversible reactions and equilibria, covering 5.2.1 Reversible reactions and dynamic equilibrium, 5.2.2 The Haber process, and 5.2.3 Changing the position of a dynamic equilibrium. Each one has a worked solution and a mark scheme showing where the marks go.