Common Mistakes With Indices in GCSE Maths
Common mistakes with indices in GCSE Maths explained through worked examples, correction methods and exam-style practice to help you protect your marks.

Indices questions often look short. That is partly why they can be dangerous. A student sees two powers, remembers something about adding or multiplying, and writes an answer before checking which rule applies.
The most common mistakes with indices in GCSE Maths come from using a correct rule in the wrong situation. The solution is not to memorise more disconnected facts. It is to recognise the structure of the expression first: are you multiplying, dividing, raising a power to another power, or dealing with a negative or fractional index?
Imagine a student correcting the errors that have been costing them marks. Instead of simply crossing out each answer, they identify why the mistake happened and attach the right rule to it. Here is the method they can follow.
A quick indices checklist
Before simplifying an expression, ask:
- Are the bases the same?
- Is the operation multiplication or division?
- Is one power being raised to another power?
- Are there coefficients outside the powers?
- Is the index zero, negative or fractional?
- Do brackets change what the index acts on?
The main laws are:
am×an=am+n a^m \times a^n=a^{m+n} am×an=am+n aman=am−n \frac{a^m}{a^n}=a^{m-n} anam=am−n (am)n=amn (a^m)^n=a^{mn} (am)n=amn a0=1 a^0=1 a0=1 a−n=1an a^{-n}=\frac{1}{a^n} a−n=an1For division, zero indices and negative indices, the base must be non-zero where required. You can review these rules in the Maths Genie Indices lesson and the accompanying Indices revision guide.
A student stops revision autopilot from taking the pencil
Common indices mistakes and how to fix them
Adding or multiplying the indices at the wrong time
Suppose the student sees:
x3×x5 x^3 \times x^5 x3×x5They write x15x^{15}x15 because they multiply 333 and 555. The confusion is understandable because multiplying indices is sometimes correct, but only when a power is raised to another power.
Here, powers with the same base are being multiplied, so add the indices:
x3×x5=x3+5=x8 x^3 \times x^5=x^{3+5}=x^8 x3×x5=x3+5=x8The expanded form explains why:
x3×x5=(x×x×x)(x×x×x×x×x)=x8 x^3 \times x^5=(x \times x \times x)(x \times x \times x \times x \times x)=x^8 x3×x5=(x×x×x)(x×x×x×x×x)=x8Use the question's operation as your cue. Multiplication between powers means add the indices, provided the bases are the same.
Adding indices when raising a power to a power
Next, the student meets:
(y4)3 (y^4)^3 (y4)3They write y7y^7y7, treating it like y4×y3y^4 \times y^3y4×y3. But the outer index means that the entire expression y4y^4y4 appears three times:
(y4)3=y4×y4×y4=y4+4+4=y12 (y^4)^3=y^4 \times y^4 \times y^4=y^{4+4+4}=y^{12} (y4)3=y4×y4×y4=y4+4+4=y12Therefore:
(y4)3=y4×3=y12 (y^4)^3=y^{4 \times 3}=y^{12} (y4)3=y4×3=y12The correction is simple: when a power is raised to another power, multiply the indices.
Applying an index to only part of a bracket
Consider:
(3x)2 (3x)^2 (3x)2A frequent answer is 3x23x^23x2. This forgets that the index applies to everything inside the brackets:
(3x)2=(3x)(3x)=9x2 (3x)^2=(3x)(3x)=9x^2 (3x)2=(3x)(3x)=9x2Compare that with:
3x2 3x^2 3x2Here, only xxx is squared. Brackets are not decoration. They tell you exactly what the index controls.
You now have the recognition method in hand, so use the Maths Genie Lessons and Question Bank for Indices to practise choosing the rule before carrying out the arithmetic.
Trying to use an index law across addition
The student then sees:
x2+x3 x^2+x^3 x2+x3They are tempted to write x5x^5x5. However, the rule for adding indices applies when powers with the same base are multiplied, not when the terms are added.
The terms x2x^2x2 and x3x^3x3 are not like terms, so they cannot be collected. The expression remains:
x2+x3 x^2+x^3 x2+x3It could be factorised as:
x2(1+x) x^2(1+x) x2(1+x)That is a factorising step, not an index law. A useful exam habit is to circle the operation sign before selecting a rule.
Thinking a zero index gives zero
The student answers:
70=0 7^0=0 70=0It feels plausible because the index is zero, but any non-zero base raised to the power zero equals 111:
70=1 7^0=1 70=1This follows from division:
7373=73−3=70 \frac{7^3}{7^3}=7^{3-3}=7^0 7373=73−3=70But any non-zero number divided by itself is 111, so 70=17^0=170=1.
Treating a negative index as a negative number
A negative index does not make the value negative. It tells you to take the reciprocal:
5−2=152=125 5^{-2}=\frac{1}{5^2}=\frac{1}{25} 5−2=521=251A common incorrect answer is −25-25−25. The minus sign is part of the index, not a sign placed in front of the final value.
For a variable:
x−3=1x3 x^{-3}=\frac{1}{x^3} x−3=x31If negative powers are causing confusion, the fractional and negative indices explanation connects negative indices with reciprocals in a clear GCSE example.
Reversing fractional indices
For a fractional index, the denominator gives the root and the numerator gives the power:
amn=(an)m a^{\frac{m}{n}}=(\sqrt[n]{a})^m anm=(na)mFor example:
1634=(164)3=23=8 16^{\frac{3}{4}}=(\sqrt[4]{16})^3=2^3=8 1643=(416)3=23=8The student may accidentally take the cube root first because 333 appears first in the fraction. Reading the denominator as the root prevents that mistake.
You can develop this further with the fractional and negative indices revision guide and the fractional and negative indices practice booklet.
Ignoring brackets around a negative base
Compare these expressions:
(−2)4=16 (-2)^4=16 (−2)4=16and
−24=−16 -2^4=-16 −24=−16In the first expression, the negative number is inside the brackets and is raised to the fourth power. In the second, the index applies to 222 before the negative sign is applied.
When copying an expression into a calculator, preserve the brackets exactly as they appear in the question.
Exam-style indices practice
Try each question before reading the answer.
Simplify a6×a4a^6 \times a^4a6×a4
The bases are the same and the powers are multiplied, so add the indices:
a6×a4=a10 a^6 \times a^4=a^{10} a6×a4=a10Simplify 12b73b2\frac{12b^7}{3b^2}3b212b7
Divide the coefficients and subtract the indices:
12b73b2=4b7−2=4b5 \frac{12b^7}{3b^2}=4b^{7-2}=4b^5 3b212b7=4b7−2=4b5Simplify (2x3)2(2x^3)^2(2x3)2
Square the coefficient and multiply the indices:
(2x3)2=22x3×2=4x6 (2x^3)^2=2^2x^{3 \times 2}=4x^6 (2x3)2=22x3×2=4x6Evaluate 272327^{\frac{2}{3}}2732
The denominator gives the cube root:
2723=(273)2=32=9 27^{\frac{2}{3}}=(\sqrt[3]{27})^2=3^2=9 2732=(327)2=32=9Write 4x−24x^{-2}4x−2 using positive indices
Move the factor with the negative index into the denominator:
4x−2=4x2 4x^{-2}=\frac{4}{x^2} 4x−2=x24Notice what has changed. The student is no longer asking, “Do I add or multiply?” in isolation. They first identify the operation and the structure, then choose the corresponding law. That small pause is what protects the mark.
Turn corrected mistakes into reliable marks
Knowing the index laws is only the first step. You also need enough practice to recognise which law an exam question is testing, particularly when coefficients, brackets and several powers appear together.
Start the Maths Genie Indices Lessons and Question Bank, complete the lesson, and then use the Question Bank to correct the indices mistakes that are still costing you marks.



