How to evaluate powers like 7−17^{-1} 7 − 1 and (35)−1\left(\frac{3}{5}\right)^{-1} ( 5 3 ) − 1 .
How powers like 12112121^{\frac{1}{2}} 12 1 2 1 and 21613216^{\frac{1}{3}} 21 6 3 1 link to square and cube calculations.
How to handle powers such as 272327^{\frac{2}{3}} 2 7 3 2 and 16−3216^{-\frac{3}{2}} 1 6 − 2 3 .
How to rewrite expressions using rules for powers.
A power is a compact way of writing repeated multiplication.
For example, 242^4 2 4 means 2 multiplied by itself 4 times.
Base and index
In ana^n a n , the base is aa a : the number or expression being powered.
The index is nn n : the small number telling you the power. The plural of index is indices.
The key index laws you need are:
am⋅an=am+n,aman=am−n,(am)n=amna^m \cdot a^n = a^{m+n}, \qquad \frac{a^m}{a^n}=a^{m-n}, \qquad (a^m)^n=a^{mn} a m ⋅ a n = a m + n , a n a m = a m − n , ( a m ) n = a mn
These work directly when the base is the same.
Rewriting powers with the same base
Suppose x=2px=2^p x = 2 p and y=2qy=2^q y = 2 q . Express 2p+q2^{p+q} 2 p + q and 2q−22^{q-2} 2 q − 2 in terms of xx x and/or yy y .
Split 2p+q2^{p+q} 2 p + q using the multiplying law.
2p+q=2p⋅2q2^{p+q}=2^p\cdot 2^q 2 p + q = 2 p ⋅ 2 q
Substitute x=2px=2^p x = 2 p and y=2qy=2^q y = 2 q .
2p+q=xy2^{p+q}=xy 2 p + q = x y
Split 2q−22^{q-2} 2 q − 2 using the dividing law.
2q−2=2q22=y42^{q-2}=\frac{2^q}{2^2}=\frac{y}{4} 2 q − 2 = 2 2 2 q = 4 y
Reciprocal
The reciprocal of a non-zero number is 1 divided by that number. In symbols, a−1=1aa^{-1}=\frac{1}{a} a − 1 = a 1 for a≠0a\neq0 a = 0 .
So a negative index does not mean “make the answer negative”. It means “put it over 1”.
The general rule is:
a−n=1ana^{-n}=\frac{1}{a^n} a − n = a n 1
Finding values with a negative index
Find the value of 6−16^{-1} 6 − 1 and (37)−1\left(\frac{3}{7}\right)^{-1} ( 7 3 ) − 1 .
A power of -1 means “find the reciprocal”.
6−1=166^{-1}=\frac{1}{6} 6 − 1 = 6 1
For a fraction, the reciprocal is found by flipping the numerator and denominator.
(37)−1=73\left(\frac{3}{7}\right)^{-1}=\frac{7}{3} ( 7 3 ) − 1 = 3 7
Negative index does not mean negative answer
Do not turn 6−16^{-1} 6 − 1 into -6. The correct value is 16\frac{1}{6} 6 1 .
Zero is different
Negative index rules need a non-zero base. For example, 0−10^{-1} 0 − 1 would mean 10\frac{1}{0} 0 1 , which is undefined.
Root
A root is the opposite of a power. a\sqrt{a} a is the number whose square is aa a , and a3\sqrt[3]{a} 3 a is the number whose cube is aa a .
The most common fractional indices are:
a12=a,a13=a3a^{\frac{1}{2}}=\sqrt{a}, \qquad a^{\frac{1}{3}}=\sqrt[3]{a} a 2 1 = a , a 3 1 = 3 a
So the denominator of the fraction tells you the type of root.
Evaluating powers of one half and one third
Find the value of 14412144^{\frac{1}{2}} 14 4 2 1 and 21613216^{\frac{1}{3}} 21 6 3 1 .
A power of 12\frac{1}{2} 2 1 means square root.
14412=144=12144^{\frac{1}{2}}=\sqrt{144}=12 14 4 2 1 = 144 = 12
A power of 13\frac{1}{3} 3 1 means cube root.
21613=2163=6216^{\frac{1}{3}}=\sqrt[3]{216}=6 21 6 3 1 = 3 216 = 6
Square roots in GCSE questions
When you are asked to “find the value” of something like 491249^{\frac{1}{2}} 4 9 2 1 , use the positive square root, so the answer is 7.
Fractional index
A fractional index is a power written as a fraction. For positive aa a , the rule is amn=(an)ma^{\frac{m}{n}}=\left(\sqrt[n]{a}\right)^m a n m = ( n a ) m .
The denominator tells you the root. The numerator tells you the power.
Root first is usually easier
For amna^{\frac{m}{n}} a n m , take the nn n th root first, then raise the result to the power mm m .
Evaluating a fractional index
Find the value of 272327^{\frac{2}{3}} 2 7 3 2 .
The denominator is 3, so take the cube root first.
273=3\sqrt[3]{27}=3 3 27 = 3
The numerator is 2, so square the result.
2723=(273)2=32=927^{\frac{2}{3}}=\left(\sqrt[3]{27}\right)^2=3^2=9 2 7 3 2 = ( 3 27 ) 2 = 3 2 = 9
A negative fractional index combines both ideas:
the fraction means root and power
the negative sign means reciprocal
Order to use
For a−mna^{-\frac{m}{n}} a − n m , do the positive fractional power first, then take the reciprocal.
Evaluating a negative fractional index
Find the value of 16−3216^{-\frac{3}{2}} 1 6 − 2 3 .
Ignore the negative sign at first and work out 163216^{\frac{3}{2}} 1 6 2 3 .
1632=(16)316^{\frac{3}{2}}=\left(\sqrt{16}\right)^3 1 6 2 3 = ( 16 ) 3
Take the square root, then cube.
(16)3=43=64\left(\sqrt{16}\right)^3=4^3=64 ( 16 ) 3 = 4 3 = 64
The negative index means take the reciprocal.
16−32=16416^{-\frac{3}{2}}=\frac{1}{64} 1 6 − 2 3 = 64 1
When the base is a fraction in brackets, the whole fraction is being powered.
Negative fractional index with a fraction
Find the value of (2764)−23\left(\frac{27}{64}\right)^{-\frac{2}{3}} ( 64 27 ) − 3 2 .
First work out the positive fractional power.
(2764)23=(27643)2\left(\frac{27}{64}\right)^{\frac{2}{3}}=\left(\sqrt[3]{\frac{27}{64}}\right)^2 ( 64 27 ) 3 2 = ( 3 64 27 ) 2
Cube root the numerator and denominator.
27643=34\sqrt[3]{\frac{27}{64}}=\frac{3}{4} 3 64 27 = 4 3
Square the result.
(34)2=916\left(\frac{3}{4}\right)^2=\frac{9}{16} ( 4 3 ) 2 = 16 9
Use the negative index to take the reciprocal.
(2764)−23=169\left(\frac{27}{64}\right)^{-\frac{2}{3}}=\frac{16}{9} ( 64 27 ) − 3 2 = 9 16
Missing the brackets
In (2764)−23\left(\frac{27}{64}\right)^{-\frac{2}{3}} ( 64 27 ) − 3 2 , the whole fraction is the base. Keep the brackets in your working so you do not only power part of the fraction.
If a power is outside brackets, it applies to everything being multiplied inside the brackets.
For example, (ab)n=anbn(ab)^n=a^n b^n ( ab ) n = a n b n .
Fractional index with a variable
Find the value of (27x6)23(27x^6)^{\frac{2}{3}} ( 27 x 6 ) 3 2 .
The denominator is 3, so take the cube root first.
27x63=3x2\sqrt[3]{27x^6}=3x^2 3 27 x 6 = 3 x 2
The numerator is 2, so square the result.
(27x6)23=(3x2)2=9x4(27x^6)^{\frac{2}{3}}=(3x^2)^2=9x^4 ( 27 x 6 ) 3 2 = ( 3 x 2 ) 2 = 9 x 4
Sometimes it is easier to split a root into smaller parts, especially with powers of 10.
Using roots with powers of 10
Find the value of 81⋅1084\sqrt[4]{81\cdot10^8} 4 81 ⋅ 1 0 8 .
Split the fourth root into two useful parts.
81⋅1084=814⋅1084\sqrt[4]{81\cdot10^8}=\sqrt[4]{81}\cdot\sqrt[4]{10^8} 4 81 ⋅ 1 0 8 = 4 81 ⋅ 4 1 0 8
Work out each fourth root.
814=3,1084=102\sqrt[4]{81}=3, \qquad \sqrt[4]{10^8}=10^2 4 81 = 3 , 4 1 0 8 = 1 0 2
Multiply the results.
3⋅102=3003\cdot10^2=300 3 ⋅ 1 0 2 = 300
To find a missing index, try to write both sides using the same base. Then compare the indices.
Solving for an unknown index
Given that 9n=279^n=27 9 n = 27 , find nn n .
Rewrite both numbers as powers of 3.
9=32,27=339=3^2, \qquad 27=3^3 9 = 3 2 , 27 = 3 3
Substitute these into the equation.
(32)n=33(3^2)^n=3^3 ( 3 2 ) n = 3 3
Use the power law.
32n=333^{2n}=3^3 3 2 n = 3 3
Match the indices and solve.
2n=3⇒n=322n=3 \Rightarrow n=\frac{3}{2} 2 n = 3 ⇒ n = 2 3
Writing a root as a power
Given that 28=2n2\sqrt{8}=2^n 2 8 = 2 n , find nn n .
Write 8 as a power of 2.
8=23\sqrt{8}=\sqrt{2^3} 8 = 2 3
Change the square root into a power of 12\frac{1}{2} 2 1 .
23=(23)12=232\sqrt{2^3}=(2^3)^{\frac{1}{2}}=2^{\frac{3}{2}} 2 3 = ( 2 3 ) 2 1 = 2 2 3
Multiply powers with the same base by adding indices.
28=21⋅232=2522\sqrt{8}=2^1\cdot2^{\frac{3}{2}}=2^{\frac{5}{2}} 2 8 = 2 1 ⋅ 2 2 3 = 2 2 5
Match with 2n2^n 2 n .
n=52n=\frac{5}{2} n = 2 5
In the exam
Look at the sign of the index first: a negative index means reciprocal.
For a fractional index, use “denominator = root, numerator = power”.
If an unknown index is involved, rewrite numbers using the same base before comparing indices.
Check yourself
Can you explain why 5−15^{-1} 5 − 1 is not -5?
Can you work out 64−2364^{-\frac{2}{3}} 6 4 − 3 2 by doing the cube root first?
If x=3px=3^p x = 3 p , can you express 3p+23^{p+2} 3 p + 2 in terms of xx x ?