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1 Unit 1: Pure Mathematics A

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Question 159

Show that the only stationary point on the graph of y=2x2−8xy = 2x^2 - 8\sqrt{x}y=2x2−8x​ is a minimum point at (1,−6)(1, -6)(1,−6).

[7]
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1 Unit 1: Pure Mathematics A Questions

  1. A Level
  2. /Maths
  3. /1 Unit 1: Pure Mathematics A

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