Given that x>0x>0x>0, answer parts (a) and (b).
Find the exact value of x x\,x that satisfies 7x54x12=147\displaystyle \dfrac{7x^{\frac54}}{x^{\frac12}}=\sqrt{147}x217x45=147.
Show that 8x−182x−3\dfrac{8x-18}{2\sqrt{x}-3}2x−38x−18, where x≠94x\neq\dfrac94x=49, may be written as 2(2x+3)2(2\sqrt{x}+3)2(2x+3).