It is given that f(x)=2x3−x2−13x+14f(x) = 2x^3 - x^2 - 13x + 14f(x)=2x3−x2−13x+14
Use the factor theorem to show that (x−2)(x - 2)(x−2) is a factor of f(x)f(x)f(x).
Hence, or otherwise, solve the equation 2x3−x2−13x+14=02x^3 - x^2 - 13x + 14 = 02x3−x2−13x+14=0, giving your answers to 2 decimal places where appropriate.