It is given that k k\,k is a positive constant and that ∫1k(32x+9)dx=8\displaystyle\int_1^k\left(\dfrac{3}{2\sqrt{x}} + 9\right)dx = 8∫1k(2x3+9)dx=8
Show that 9k+3k−20=09k + 3\sqrt{k} - 20 = 09k+3k−20=0.
Hence, using algebra, find the value of kkk.