The vectors u=(2λ+1)i+(λ−3)j\mathbf{u} = (2\lambda + 1)\mathbf{i} + (\lambda - 3)\mathbf{j}u=(2λ+1)i+(λ−3)j and v=5i−2j\mathbf{v} = 5\mathbf{i} - 2\mathbf{j}v=5i−2j are parallel.
Find the value of λ\lambdaλ.