Prove that:
sin4α−cos4α≡1−2cos2α\sin^4 \alpha - \cos^4 \alpha \equiv 1 - 2\cos^2 \alphasin4α−cos4α≡1−2cos2α
Hence solve, for 0≤α≤3600 \leq \alpha \leq 3600≤α≤360, the equation,
sin4α−cos4α=0.5 \sin^4 \alpha - \cos^4 \alpha = 0.5 sin4α−cos4α=0.5225 exam-style questions on WJEC A Level Maths 3.5 Trigonometry (A-level only), covering 3.5.1 Trigonometry (A-level only), 3.5.2 Trigonometry (A-level only), 3.5.3 Trigonometry (A-level only), 3.5.4 Trigonometry (A-level only), 3.5.5 Trigonometry (A-level only), 3.5.6 Trigonometry (A-level only), 3.5.7 Trigonometry (A-level only), and 3.5.8 Trigonometry (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.