It is given that
(sinθ+6cosθ)2+(3sinθ−2cosθ)2=28(\sin\theta + 6\cos\theta)^2 + (3\sin\theta - 2\cos\theta)^2 = 28(sinθ+6cosθ)2+(3sinθ−2cosθ)2=28
and that θ \theta\,θ is obtuse.
Find the exact value of sinθ\sin\thetasinθ. Fully justify your answer.
Find the exact value of cos2θ\cos 2\thetacos2θ.
Find the exact value of tanθ\tan\thetatanθ, giving your answer in surd form.
225 exam-style questions on WJEC A Level Maths 3.5 Trigonometry (A-level only), covering 3.5.1 Trigonometry (A-level only), 3.5.2 Trigonometry (A-level only), 3.5.3 Trigonometry (A-level only), 3.5.4 Trigonometry (A-level only), 3.5.5 Trigonometry (A-level only), 3.5.6 Trigonometry (A-level only), 3.5.7 Trigonometry (A-level only), and 3.5.8 Trigonometry (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.