You may use the identity sin3x≡3sinx−4sin3x\sin 3x \equiv 3\sin x - 4\sin^3 xsin3x≡3sinx−4sin3x.
Solve, for 0≤x<π0 \leq x < \pi0≤x<π, the equation
8sin3x−6sinx+1=08\sin^3 x - 6\sin x + 1 = 08sin3x−6sinx+1=0
Give your answers in terms of π\piπ.
225 exam-style questions on WJEC A Level Maths 3.5 Trigonometry (A-level only), covering 3.5.1 Trigonometry (A-level only), 3.5.2 Trigonometry (A-level only), 3.5.3 Trigonometry (A-level only), 3.5.4 Trigonometry (A-level only), 3.5.5 Trigonometry (A-level only), 3.5.6 Trigonometry (A-level only), 3.5.7 Trigonometry (A-level only), and 3.5.8 Trigonometry (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.